Wavelength-Frequency-Energy Problems #11 - 20 | Go to Part Two of Light Equations |
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500.0 nm = 500.0 x 10¯9 m = 5.000 x 10¯7 m
E = hc / λ
a) 92.0 kJ/mol
b) 8.258 x 10-4 kJ/mol
c) 1870 kJ/mol
1.345 x 10-7 m = 134.5 x 10-9 m = 134.5 nm
No.
λν = c(2.80 x 10-10 m) (x) = 3.00 x 108 m/sx = 1.07143 x 1018 s-1
AgCl ---> Ag + Cl
Make sure to use J rather than kJ.
Use Avogadro's Number.
Hint: these energies often have the magnitude of 10-19 J.
a) 4.50 mol times Avogadro's Number
b) that answer times three.
Wavelength-Frequency-Energy Problems #11 - 20 | Go to Part Two of Light Equations |
Return to Part One of Light Equations | Return to Electrons in Atoms menu |